how do i graph y=3/4x+5
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At 7/7/08 04:57 PM, Bugmenot wrote: ugh calculus is killing me
That's definitely algebra.
Also, pay attention in skewl.
At 7/7/08 04:57 PM, Bugmenot wrote: ugh calculus is killing me
THE TITLE IS KILLING MY BRAIN
HTML you may use <a> link
This is pretty easy stuff man. You have to use the formula y=mx+c y is the y point[on the graph] m is the graident [the slope of the line] and c is the y intercept[where the line cuts the y axis]
just make up a x point say 3 then sub it into the eqn so you get y=3/4*3+5, you get your answer so you get the points (answer from eqn, 3) then do it again and you have two points to plot your line....
Exhale
Start at y = 5, for every 4 units right, go 3 up.
The rainforest burns the same as any other forest.
Smith & Wesson, Curing the Blues Since 1864.
Have a hypothetical bucket.
That's algebra, it follows the y=mx+b formula. B, or 5, is the Y intercept, so the slope(m) would intercept the Y line at 5. And 3/4 is the slope.
So it would look like this.
Man, I haven't done this stuff since 8th grade haha.
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At 7/7/08 05:02 PM, Mr-Contradiction wrote: Start at y = 5, for every 4 units right, go 3 up.
Or is it 3 right and 4 up... I just use a fucking calculator.
The rainforest burns the same as any other forest.
Smith & Wesson, Curing the Blues Since 1864.
Have a hypothetical bucket.
Oh yeah, its called 'the equ. of a straight line' GEEZE!
At 7/7/08 05:04 PM, Mr-Contradiction wrote:At 7/7/08 05:02 PM, Mr-Contradiction wrote: Start at y = 5, for every 4 units right, go 3 up.Or is it 3 right and 4 up... I just use a fucking calculator.
y = slope(x) + y-intercept
slope = rise/run
thus the line intercepts 5 on the y axis and rises 3 and moves rightward 4.
fucking pre-algebra
At 7/7/08 05:07 PM, NGCA wrote:At 7/7/08 05:04 PM, Mr-Contradiction wrote:y = slope(x) + y-interceptAt 7/7/08 05:02 PM, Mr-Contradiction wrote: Start at y = 5, for every 4 units right, go 3 up.Or is it 3 right and 4 up... I just use a fucking calculator.
slope = rise/run
thus the line intercepts 5 on the y axis and rises 3 and moves rightward 4.
fucking pre-algebra
Well pre-algebra got wiped from my head in Calculus IV and Computational Fluid Dynamics... Computers do it faster.
The rainforest burns the same as any other forest.
Smith & Wesson, Curing the Blues Since 1864.
Have a hypothetical bucket.
Wait, isn't the equation 3/(4x), rather than (3/4)x?
What is this, Amateur Hour?
That's not Calculus, it's basic Algebra.
At 7/7/08 05:11 PM, HeartbreakHoldout wrote: Wait, isn't the equation 3/(4x), rather than (3/4)x?
No, the original poster is just a moron who didn't post the equation correctly in the title.
Have faith in NGCA.
At 7/7/08 05:23 PM, NGCA wrote: No, the original poster is just a moron who didn't post the equation correctly in the title.
Have faith in NGCA.
No need to toot your own horn over something so basic.
It's a straight line, every time it goes up once, it goes across four times. It starts on the point, 0,5.
Not my real name!
At 7/7/08 05:24 PM, HeartbreakHoldout wrote:At 7/7/08 05:23 PM, NGCA wrote: No, the original poster is just a moron who didn't post the equation correctly in the title.No need to toot your own horn over something so basic.
Have faith in NGCA.
I'll toot my own horn whenever it pleases me or visa-versa.
