Ugh, it sickens me to do this...

[DanAbnormal]

I dont know why im bothering here, but im desperate.

Is anyone here very good at maths, I need help with my referred paper.

Why am I here?

[BananaBreadMuffin]

At 8/19/08 07:01 PM, DanAbnormal wrote: I dont know why im bothering here, but im desperate.

Is anyone here very good at maths, I need help with my referred paper.

Why am I here?

Man, I haven't seen you for a wihle.

Sup?

[wwhhaatt]

At 8/19/08 07:01 PM, DanAbnormal wrote: I dont know why im bothering here, but im desperate.

Is anyone here very good at maths, I need help with my referred paper.

Why am I here?

You wanted to see BBR's replacement/

[MrVideogame]

what year/grade are you in? if its any higher then year 11(16-17 y.o) I cant help.

*shock* a genuine reply!

[DanAbnormal]

At 8/19/08 07:01 PM, BananaBreadMuffin wrote:

At 8/19/08 07:01 PM, DanAbnormal wrote: I dont know why im bothering here, but im desperate.

Is anyone here very good at maths, I need help with my referred paper.

Why am I here?

Man, I haven't seen you for a wihle.

Sup?

I havent been here for about a year. I went to university and discovered there's so much more to life! I've had my innings as an internet dweeby.
But now im alone in Scotland trying to complete a paper with none of my notes or books, and the internet can never give you exactly what you want, despite it being as big as Paris hilton's vagina. Help forums run so slowly aswell. The only forum ive ever known to run so fast is this one, but the chances of finding anyone who can help are slim.

Dunno why I bothered. But I guess it's interesting to see what's going on here after so long, sort of...

[Slayer3751]

I suck at maths. You get no help from me.

[BlueFlameSkulls]

Please come back to us Dan.

[Seriana]

Ask away

[Genocide]

You're here because newgrounds.com is obviously consistent of the smartest mathematicians ever.

[DanAbnormal]

At 8/19/08 07:08 PM, BlueFlameSkulls wrote: Please come back to us Dan.

Dont see that happening. My life's so much better since leaving this place. I remember back in the old days when people got upset about regulars leaving, it was like a big family. No ones here anymore, just a handful of the oldies, doesn't look any better if im honest. Guess it's subjective though, I left because I had something I thought would be better to do, and it was. Who knows, I may have still been here if I hadnt gone to uni.
Haha, im beginning to see how this could look like some elaborate publicity stunt. But im afraid im not here to stay. But I might look over some of my old flash animations :D

At 8/19/08 07:10 PM, Genocide wrote: You're here because newgrounds.com is obviously consistent of the smartest mathematicians ever.

Haha, I realised after I posted this probably wasnt the best idea. Im a bit drunk and stressed at this paper, so I came here for some reason...
At the risk of sounding pretentious I dont think anyone will be able to actually help me, even if theyre a maths genius.
Interesting to see NG again though.

[1337]

Pop the big question?

[videogamer0810]

I'll be happy to help. I did take Calculus 2 in college, after all. Need to find the area under a curve? I can help you... probably.

[TheBlackDahliaMurder]

Heh, I remember you.

And you keep insisting we can't help, yet you aren't giving us your math problem.

[Genocide]

Are you going to tell us the damn problem, or am i going to have to start guessing?

[HeartbreakHoldout]

I just finished my first year of university with (I assume) decent marks. Could I be of any help?

[Senmetsu]

At 8/19/08 07:26 PM, Genocide wrote: Are you going to tell us the damn problem, or am i going to have to start guessing?

I was just thinking that...Like TELL ME THE PROBLEM.

I ended up deciding he wanted the chem formula for photosyntesis, so here you have it
6CO2+6H2O+Sunlight=C6H12O6+6O2

There you go.

[DanAbnormal]

Okay, okay..

Problem 1:

Find the stationary points of

f(x,y) = e^((-x^3) + 3x - (y^2))

and determine their nature.

Problem 2: (I think this one's slightly easier, but im not thinking too well)

f(x) = xlnx

Find the solutions of the equation f(x) = 0
Find any minima/maxima that f(x) has.

Problem 3:

If
z = (1/x)f(y/x)

show that

x(dz/dx) + y(dz/dy) + z = 0
(The above derivatives are partial derivatives)

Would be cool if someone helped..

[lilcheeselad]

CHEERIO SIG

[videogamer0810]

Problem 2 is probably giving you trouble, since both parts are trick questions.

Problem 2: (I think this one's slightly easier, but im not thinking too well)

f(x) = xlnx

Find the solutions of the equation f(x) = 0

Easy. ln x goes to -infinity as x approaches 0. So there are no solutions for x, only a limit.

Find any minima/maxima that f(x) has.

Also, no minima or maxima. As x increases, ln x increases, so x ln x must also be always increasing. Therefore, there cannot be any troughs or peaks.

[HeartbreakHoldout]

At 8/19/08 07:43 PM, videogamer0810 wrote: Easy. ln x goes to -infinity as x approaches 0. So there are no solutions for x, only a limit.

Then you have ln1 which equals 0. Surely x=1 would be an answer?

[videogamer0810]

At 8/19/08 07:43 PM, videogamer0810 wrote:

Find the solutions of the equation f(x) = 0

Easy. ln x goes to -infinity as x approaches 0. So there are no solutions for x, only a limit.

Oops, I misread it. Sorry.

Correct answer: the graph of ln x intersects the x-axis at x=1. The same is true for 2 ln x, 5 ln x, 3.14159 ln x, and any other ? ln x in existence.

When f(x) = 0, x = 1.

This is the right answer, I'm sure of it.

[Monodi]

At 8/19/08 07:01 PM, DanAbnormal wrote: I dont know why im bothering here, but im desperate.

Is anyone here very good at maths, I need help with my referred paper.

Why am I here?

Jesus christ, long time no see Danny

[1337]

Are you guys fucking rocket scientists or what??

[Senmetsu]

At 8/19/08 07:43 PM, videogamer0810 wrote: Problem 2 is probably giving you trouble, since both parts are trick questions.

Problem 2: (I think this one's slightly easier, but im not thinking too well)

f(x) = xlnx

Find the solutions of the equation f(x) = 0

Easy. ln x goes to -infinity as x approaches 0. So there are no solutions for x, only a limit.

Find any minima/maxima that f(x) has.

Also, no minima or maxima. As x increases, ln x increases, so x ln x must also be always increasing. Therefore, there cannot be any troughs or peaks.

You said a bunch of words I didn't understand. I guess I can't take my algebra 1 information and help that much. I suck at math..but I figured it was worth a shot :D

At least I remember y=mx+b and something = y2-y1/x2-x1

[BananaBreadMuffin]

I could've sworn we did shit like this in A-level. I'm too out of practice to help you now I'm afraid, but I'm pretty sure we did all of those sorts of things in core maths 4.

[LordZeebmork]

Shit, I should remember this stuff. I guess that shows how much attention I paid in school.

Also, any base logarithm of 1 is 0, because any number to the 0th power is 1. (I'm too lazy to use the quote feature.)

[DanAbnormal]

At 8/19/08 07:48 PM, videogamer0810 wrote: Oops, I misread it. Sorry.

Correct answer: the graph of ln x intersects the x-axis at x=1. The same is true for 2 ln x, 5 ln x, 3.14159 ln x, and any other ? ln x in existence.

When f(x) = 0, x = 1.

This is the right answer, I'm sure of it.

That seems right to me, however the question asking for solutions is worth 4 marks and the question asking for maxima/minima is worth 5, which fucking throws me off big time.
You can make the derivative of xlnx = 0, which gives an answer of x = 1/e.
Dunno what to do with it though...

But I want to say you were correct.

At 8/19/08 07:49 PM, 1337 wrote: Are you guys fucking rocket scientists or what??

I study Astronomy, so pretty much.
However im doing quite badly.

[HeartbreakHoldout]

At 8/19/08 07:36 PM, DanAbnormal wrote: Problem 1:

Find the stationary points of

f(x,y) = e^((-x^3) + 3x - (y^2))

and determine their nature.

Do you find the partial derivatives for x and y and then use the chain rule or something? This was only 6 months ago and I've totally forgot. Either that or I don't know this yet :S

[DanAbnormal]

At 8/19/08 07:57 PM, HeartbreakHoldout wrote:

At 8/19/08 07:36 PM, DanAbnormal wrote: Problem 1:

Find the stationary points of

f(x,y) = e^((-x^3) + 3x - (y^2))

and determine their nature.

Do you find the partial derivatives for x and y and then use the chain rule or something? This was only 6 months ago and I've totally forgot. Either that or I don't know this yet :S

Yeah I dont even know if my partial derivatives are right, and if they are what im supposed to do with them. I wish I could write out my process, because typing it out looks so confusing and messy!

[X-Gary-Gigax-X]

At 8/19/08 07:01 PM, DanAbnormal wrote: Why am I here?

Because YOU'RE A JEEEEWWWWWW