A problem with eval()

[NinoGrounds]

Hey guys, it's been a few days since I was here. Tom was talking about potential username "lockdown" so I swaped my username. It's me - SexOnStreet (Nino).

Alright, here we go:
I need to make a variable via eval() - user defines the name of that variable via $op['var'].

I came with this:
ob_start();
echo $op['var'];
$gotop = ob_get_contents();
eval("ob_get_contents() = $op1.$string.$op2;");
ob_end_clean();

But IT doesn't work -- $op['var'] is nicely filled with, for example, $dtxt. But the variable isn't made.

Suggestions, please?

[NinoGrounds]

And yes, I know that third line isn't necessary.

[henke37]

Why are you using eval? If you ask me it should at the very lest come dissabled by default.

[NinoGrounds]

At 11/11/06 07:37 AM, henke37 wrote: Why are you using eval? If you ask me it should at the very lest come dissabled by default.

Then how would I do that?

1) User supplies an argument in a function.
2) I gotta make that variable which is supplied in argument and fill it with string.

eval() is the only choice

[authorblues]

At 11/11/06 11:40 AM, NinoGrounds wrote: eval() is the only choice

really? ever used double dollarsigns?

$myvariablename = 'bob';
$$myvariablename = 'tom';

echo $bob;
?>

[NinoGrounds]

At 11/11/06 04:48 PM, authorblues wrote: really? ever used double dollarsigns?

nope