VisualBasic

[Vortex]

Is there any one there thats good at visual basic programming and can help me an easy program that i have to do for HW in my VB class. its a simple program but i dont know the code to use to get it to work , if theres any one willing to help ill tell you what i have to do
( i doubt its more than5 lines of code , the project sounds imple)

[Vortex]

C'mon , Any body ! ='(

[Casualty]

Could you at least explain the project? =P

[Vortex]

Yes =p
the project is
you make a lable that says " enter a two digit number in the text box"
i made that lable , named it lblinstructions
and i made the text box , no text in it , and names it txtdigits
the object is say you type in the nmber 56
theres a lable that says digit one
and a lable that says digit two
next to digit one , 5 is supposed to come up
next to digit to 6 is supposed to come up
if you write 23 in the text box , digit one should have 2 next to it
and digit two should have a 3 next to it and so on

i made a lable that says digit one:
and a lable that says digit two:
with blank lables next to em both , each named lblnum1 and lblnum2
i can get the full number you type to come up in one with

Dim lblnum1 As Integer

then for the button that makes the program show the two numbers
i wrote
lblnum1.caption=txtdigits
but i dont know how to split it up so the first number comes up in lblnum1 and the second digit comes up in lvlnum2

i know this is long but i tried to explain it as clearly as i could , any help id <3

[Vortex]

*Sniffles*

[Casualty]

It's homework so I won't make it for you =P But if you search Google for "Visual Basic Left Right Function" you should find something.

This is A way of doing this, there are others but this works.

[authorblues]

At 11/3/06 03:27 PM, Casualty wrote: This is A way of doing this, there are others but this works.

a very poor way, i would say. lets see if i can remember basic syntax...

Dim FullNum as Integer
Dim DigOne as Integer
Dim DigTwo as Integer

FullNum = 23

DigTwo = FullNum Mod 10
DigOne = FullNum \ 10