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I have a good paradox. I like this one, and you really have to think about it.

This statement is false.

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At 4/20/05 11:06 PM, ZombieLincoln wrote: And so, the first puzzle:

They are all really bats and not people since you didn't say they were people.
There are old people below them with a flashlight crossing the bridge.
You said people again so it doesn't matter.

Anyway, they all go to the end in 10 minutes and wait around for 7 minutes, making it 17 minutes.

Or:

They cross the bridge like you said and use something Einstien wrote to go back in time and make it 17 minutes.

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Okay, I have an idea... Why don't they just throw the flashlight back once they've crossed?

In that case, (provided nobody drops anything) tenly, and five...-ly would walk across, and tenly being the NFL superstar he is would toss the flashlight across the bridge to toot and the uni-guy. They would walk across, and everyone would live happily after. Elapsed time for the bridge-crossing: 16 minutes, due to uni-guy's conditional crap-spasms. The flashlight toss would take about one minute, because toot does not know how to catch... TOTAL:17 minutes. w00t.

And, also, what is the significance of the flashlight? You never specified the time of day... it could be sunny. Or, maybe the flashlight acts as an augumented form of MACE, to weild off the bass, raven, Ann coulters, and other wild beasts. I don't know. It dont make no cent... :p

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Onerly picks Tenly & the flashlite up crosses -1min.
onerly goes back -1min.
onerly throws fivel over his shoulder- 1min.
onerly goes back -1min.
Onerly is tired so tooper picks him up(with flash lite of course) crosses the bridge 2min.
Done in 6 minutes motherfu---r , no muss no fuss ,if onerly was in better shape we could have finished in 5 minutes

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At 4/21/05 07:04 PM, catmaster1010 wrote: I have a good paradox. I like this one, and you really have to think about it.

This statement is false.

Modification:

The statement below is false.
The statement above is true.

fun stuff =D

At 4/21/05 07:23 PM, ilsoft wrote:
They are all really bats and not people since you didn't say they were people.
There are old people below them with a flashlight crossing the bridge.
You said people again so it doesn't matter.

This puzzle was already solved. But fine, they're bats.

Anyway, they all go to the end in 10 minutes and wait around for 7 minutes, making it 17 minutes.

Or:

They cross the bridge like you said and use something Einstien wrote to go back in time and make it 17 minutes.

I....I never thought of that. That's a new solution. Nice.

At 4/21/05 07:34 PM, NarcolepticAlarmClok wrote: Okay, I have an idea... Why don't they just throw the flashlight back once they've crossed?

Why bother? As AvatarEgo already showed, you don't need any of your trendy creative thoughts to do this puzzle. The solution was simple and elegant.

And, also, what is the significance of the flashlight? You never specified the time of day... it could be sunny. Or, maybe the flashlight acts as an augumented form of MACE, to weild off the bass, raven, Ann coulters, and other wild beasts. I don't know. It dont make no cent... :p

I often wonder about the significance of flashlights as well.

At 4/21/05 07:38 PM, morefngdbs wrote: Onerly picks Tenly & the flashlite up crosses -1min.
onerly goes back -1min.
onerly throws fivel over his shoulder- 1min.
onerly goes back -1min.
Onerly is tired so tooper picks him up(with flash lite of course) crosses the bridge 2min.
Done in 6 minutes motherfu---r , no muss no fuss ,if onerly was in better shape we could have finished in 5 minutes

Sweet. I'm glad this puzzle has been so thoroughly solved by you guys! Hell, I'm ashamed of posting such an easy one.

At 4/21/05 06:44 PM, donthurtme wrote: Well, i added up all the probabilities (1/365 + 2/364 + 3/363 + 4/362 etc.), and got an answer of 19, but I believe this has been suggested before. The 18th person has a probability of just 48%, the 19th is 54%.

your math is wrong, but at least you're answering the right question! =D The probabilities don't just get added up. Why would you add the probabilities for completely different situations?

Also, once you have 3 or more people, the probabilities are stranger. You could have multiple duplicate birthdays or triple-birthdays, or more...

This question may be too hard for most of you, which is ok. Here it is again, for you who are good enough to read the first post, but not interested in reading the ones in between:

Puzzle #3

Some bored guy decides to start a new thread on the NG BBS. He tries to imagine a thread that would be something lots of people would contribute to! After much consideration, he decides to make a birthday thread.

He opens with "hey every1! I thought it would be cool to make a thread for peeps who are having there bibrthdays. its ok if your birthday isnt today, just tell everyone what day it is and we can see who has teh same birthday as you LOL!"

How many people must post their birthdays on the thread for there to be a 50% chance that there is at least one duplicate birthday?

Good luck to those who try =)

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Oh well, never was much good at maths. Is way over my head now neway. Good luck to anyone else that gives it a shot.

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I'll give a bump cuz Im friggin stumped... never had to deal much with probablilities so I'm gonna leave it for the math majors >.<

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Let B = event no one in the group shares the same birthday
Let Bc = event at least 2 people share same birthday
P(B) = (365/365)(364/365)......(343/365) = 0.493
P(Bc)= 1 - 0.493 = 0.507

so.. 23 :)

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Here is a fairly easy one:

A man has a serious desease... he needs to take one "A" Pill and one "B" pill every moring, and every night.. or else he will instantly die a horrible death.
Now this man is going on a one day business trip, he'll be away from his house for no more than 24 hrs.

As he packs he figures he'll need a total of 4 pills, 2 "A" pills and 2 "B" pills
in his rush to pack, he grabs to of each pill throws them together in one bottle and into his suitcase the bottle goes.

The next morning he wakes in his hotel room, out of habbit begis to look for the bottle of pills. Finds them and goes into the bathroom He opens the jar and pours the four pills on the counter and in an instant he realizes his dilema.

All four pills look identical... there is no way to tell the "A"s from the "B"s... but he needs to eat an A and a B right now or he will die.

He cannot eat them all.. or he will die later on that night when he needs them again, he cannot eat two A's or 2 B's because it is not the right balance in chemicals.

How does he solve this dilema and eat exactly 1 "A" pill and 1 "B" pill?

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At 4/22/05 03:00 PM, AvatarEgo wrote: Let B = event no one in the group shares the same birthday
Let Bc = event at least 2 people share same birthday
P(B) = (365/365)(364/365)......(343/365) = 0.493
P(Bc)= 1 - 0.493 = 0.507

so.. 23 :)

Glory be! Well solved, sir! *gives spoils*

And now to check out your puzzle ^.^

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AH! Broken!

*fixes*

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no one can figure out this 4th riddle?
I even have a (not so good) award picture in the works

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Eat half of every pill. Total is 1 A and 1 B (its almost 4 in the morning and I am pretty drunk, can still work that out!!)

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It sounds like fun but I am way too tired to think of a Math equation. I'll come bacl in teh morning. Good night NG!

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At 4/22/05 10:55 PM, donthurtme wrote: Eat half of every pill. Total is 1 A and 1 B (its almost 4 in the morning and I am pretty drunk, can still work that out!!)

yeah I told you it was easy.. so here's your crappy prize