Oh my fuck, you people need to stop dicking around and just answer his question.
a = 229 in/s^2 (I'm assuming this is what you meant, because I don't know how acceleration in square inches works in reality)
v0 = 0 in/s
v1 = 60 m/h = 1056 in/s (ffffffffffFFFFFFFFUCK IMPERIAL UNITS)
t1 (time to reach 60 mph)
D (distance covered between t0 = 0 and t1)
at t = 0, v = 0 and D = 0
DO SOME MATH:
a = 229 in/s^2
integrate w.r.t. time to find:
v = 229t in/s
D = (229/2)t^2 in
(both integration constants are zero due to the initial conditions, trivial calculations omitted)
1056 in/s = 229(t1) in/s
t1 = 4.6114 s
D = (229/2)(4.6114^2) = 2434.84 inches
= 202.9 feet
= 0.0384 miles
For fuck's sake
At 6/17/11 10:03 AM, JaY11 wrote:
Inches and miles per hour? Please tell me physics in the US is not based around the imperial system?
Prepare to have your mind blown: Many engineers in the real world have to work around imperial units simply because a lot of instruments are designed or manufactured in the US.