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3.80 / 5.00 4,200 ViewsI have a Math 152.01 test coming up here soon (Integral Calculus for those of you who don't talk OSU language). It's over partial fraction decomposition. Anybody care to try and give me a quick run over of all of this?
Who's your warden, baby?
At 2/23/10 10:16 AM, Saxturbation wrote: I have a Math 152.01 test coming up here soon (Integral Calculus for those of you who don't talk OSU language). It's over partial fraction decomposition. Anybody care to try and give me a quick run over of all of this?
Yeah sure, this guy is really good at math.
I lurk these forums like a fat kid lurks cake.
1/2 x 1/2 = 1/4
No seriously, what the fuck is that?
At 2/23/10 10:17 AM, fuzzies wrote: Yeah sure, this guy is really good at math.
Nah I haven't found any good guides on Google. Sad I know right?
Who's your warden, baby?
At 2/23/10 10:17 AM, LiquidOoze wrote: 1/2 x 1/2 = 1/4
No seriously, what the fuck is that?
think of it as decimals
.5 (1/2) X .5 = .25 (1/4)
Dude, I'm 13 and I know this shit.
At 2/23/10 10:20 AM, Yacazuma wrote:At 2/23/10 10:17 AM, LiquidOoze wrote: 1/2 x 1/2 = 1/4think of it as decimals
No seriously, what the fuck is that?
.5 (1/2) X .5 = .25 (1/4)
Dude, I'm 13 and I know this shit.
That's not partial fraction decomposition. This is.
Who's your warden, baby?
Yeah there's something that you could do OP.
I think it's called tutoring.
Well, I've got news for you pal, you ain't leadin' but two things right now: Jack and shit... and Jack left town.
Sig by Her
At 2/23/10 10:24 AM, Saxturbation wrote: That's not partial fraction decomposition. This is.
OH MY JESUS WHAT IS THAT SHIIIIT
head 'splosion
At 2/23/10 10:20 AM, Yacazuma wrote:At 2/23/10 10:17 AM, LiquidOoze wrote: 1/2 x 1/2 = 1/4think of it as decimals
No seriously, what the fuck is that?
.5 (1/2) X .5 = .25 (1/4)
Dude, I'm 13 and I know this shit.
Lmfao, please, leave this thread.
Ok, partial fraction decomposition. There is a lot to it...several different methods.
The simplest version is say... 1/[(ax+b)(cx+d)], which can be written out as A/(ax+b) + B/(cx+d), which makes perfect sense if you think of how any numerical fraction works... So write the original expression, set it equal to your decomposed expression, start by multiplying by the denominator of the original expression, and then set x so you can solve for one variable. Replace the variable, change x and solve for the next.
It's not an easy technique to learn right before a test though.
Yeah suck my darkbrown...whut nvm.
I was being sarcastic about my little fraction post, but I am just too lazy to grab a English-Dutch dictoniary to search for whatever decomparis.... whatever that said, means.
At 2/23/10 10:24 AM, Saxturbation wrote:At 2/23/10 10:20 AM, Yacazuma wrote:That's not partial fraction decomposition. This is.At 2/23/10 10:17 AM, LiquidOoze wrote: 1/2 x 1/2 = 1/4think of it as decimals
No seriously, what the fuck is that?
.5 (1/2) X .5 = .25 (1/4)
Dude, I'm 13 and I know this shit.
I shit myself.
"I do not fear death. I had been dead for billions and billions of years before I was born, and had not suffered the slightest inconvenience from it."
- Mark Twain
Where:
(integral):1/x^2-4
(integral):1/(x-2)(x+2)
LHS = A/x-2 + B/x+2
Now, from the LHS, multiply out the denominator.
LHS = A(x+2) + B(x-2) (EQUATION 1)
Follow through
LHS = Ax + 2A + BX -2B
Simplify.
LHS = (A+B)x + 2A-2B
Now, look at the individual factors, compare what you have to the like terms in the numerator
A+B, compares to the x term in the numertator, since there isn't an x term, it can be said that
A+B=0.
Now, 2A-2B=1
Solve, and substitute A and B into equation 1, and integrate.
(Miss anything?)