Forum Topic: Why won't this function work..?

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Night-Mare

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Posted at: 10/5/09 06:03 AM

Night-Mare FAB LEVEL 19

Sign-Up: 02/17/05

Posts: 4,577

var m1:Number = 0;
var m2:Number = 1;
function mCheck(a, b) {
	b = a;
}
mCheck(m1, m2);
t = m1+'-'+m2;
trace( t);

This function SHOULD trace 0-0.
But it doesn't even change the variable of m2 to m1.

Does anybody know the reasoning behind this?

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Montycarlo

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Posted at: 10/5/09 06:06 AM

Montycarlo LIGHT LEVEL 19

Sign-Up: 03/14/05

Posts: 742

You're passing the value of the variables as arguments, not the memory addresses of the variables.

Although practicality beats purity.
Errors should never pass silently.
In the face of ambiguity, refuse the temptation to guess.


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Night-Mare

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Posted at: 10/5/09 06:09 AM

Night-Mare FAB LEVEL 19

Sign-Up: 02/17/05

Posts: 4,577

Oh, I forgot they didn't actually pass the variable along with it.

My mistake, thanks mate. :)

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