whats that code

[piggy123]

whats hat as2 code where if they get in a certin radies of a guy something happens?

[Paranoia]

It's determined via Pythagoras:

distance * distance = x * x + y * y;

[piggy123]

where do i fill in the radies though?

[UnknownFury]

At 8/1/09 12:19 PM, Paranoia wrote: It's determined via Pythagoras:

distance * distance = x * x + y * y;

Get the x distance and y distance and add the squares and compare it to the sum of the radii squared.

radii = (r1 + r2) * (r1 + r2)

xd = x1 - x2
yd = y1 - y2
d = xd * xd + yd * yd

if(d < radii) ...

[piggy123]

i admit it i suck at math but here is the guys radies

x = 260.6 y = 197.1

[piggy123]

please can you help?

[Anamethatworks]

perhaps it would be easier if you draw/do the problem on paper first.

you're problem right now is that you know the x line and y line of a triangle between the two points (absolute difference between x1 and x2 = x line, same with y)
so you know two sides of a triangle of which one angle is 90 degrees.
all you need to do now is calculate the hypotenuse (diagonal side)

which as stated earlier is easy using
a^2 + b^2 = c^2 (xline^2 + yline^2 = hypotenuse^2)
here's a picture from wikipedia

so after that just get the square root of c and there you go, the length of the hypotenuse which is the distance between the two points

(in case you don't quite get which point is which, corner a c is the coordinates of 1 point, a b is were xline and yline meet, and b c is the coordinates of your second point)

[piggy123]

what did you just say?

[UnknownFury]

The radius of a circle is the width or height (they should be the same) divided by 2. If you just want to do an approximate with a bounding circle of a non circular object then take whichever is greater height or width and treat that as your diameter.

Also be patient. You didn't want any time at all for an answer.

At 8/1/09 01:05 PM, Anamethatworks wrote: so after that just get the square root of c

It probably doesn't matter as far as this is concerned, but it's much faster to compare the radii squared than it is to square root the distance and compare to the sum of the radii. Squaring takes a fraction of the time square rooting does.

[Anamethatworks]

true its faster to do it like that, but the point is understanding the math behind the Pythagorean theorem.
And to get the actual distance you need to know c and not c^2
here's a picture explaining what I said in the other post... again it looks awful I know.. just made it in paint a few seconds ago

[AnalogStick]

Makes you wonder what they teach kids these days if they don't know basic things like Pythagoras theorem.

[Anamethatworks]

yeah no kidding, it's one of the most basic things ever.
and you can't really do much without it.

kinda sad really

[hoboguise]

wow, im a teen myself but i found this thread amusing with a kid who doesnt understand how pythagoras works, some advice to piggy123 is not to attempt any physics at all if he doesnt even understand how pythagoras theorum work, i wonder if he's been taught about |sin|cos|tan|