Geometry brainfart...

[Johnny]

Getting a random point, where the point mustreside at some point inside of a circle.

1st 2 steps... no problem.

1) Generate a random angle.
2) Generate a random distance, where the max is the radius of the circle.

Yet, I can't finish the process of getting the X and Y of the new point.
I'm not sure if I have to convert to radians, and apply sin/cos/tan (or inverses).

I feel like a retard.
Thanks!

[El-Presidente]

x = distance * Math.cos(radians)
y = distance * Math.sin(radians)

Hypothetically, it doesn't matter if it's in radians or degrees, because it will always be within the domain of sin and cos. And the distance is the radius.

[RobertJ]

I feel like a retard.
Thanks!

YOU feel like retard? I don't even know trigonometry yet. :(

[DawnOfDusk]

At 4/28/09 10:27 PM, El-Presidente wrote: x = distance * Math.cos(radians)
y = distance * Math.sin(radians)

Hypothetically, it doesn't matter if it's in radians or degrees, because it will always be within the domain of sin and cos. And the distance is the radius.

Another note: Since I'm a mega h8r of radians, I also find myself converting shit from radians to degrees.... it's really just as simple as...

( ValueInRadians * 180 ) / Math.Pi = ValueInDegrees
--and vice versa--
( ValueInDegrees * Math.Pi ) / 180 = ValueInRadians

[Johnny]

At 4/28/09 11:14 PM, DawnOfDusk wrote: Another note: Since I'm a mega h8r of radians, I also find myself converting shit from radians to degrees.... it's really just as simple as...

( ValueInRadians * 180 ) / Math.Pi = ValueInDegrees

Yeah, I've done a bunch of work with angular velocity (x+= Math.sin(angle)*speed)... but for the life of me couldn't figure out how to plot a simple point inside a circle.

Thanks Elly-P. Figured it was something simple.