Help with bouncing ball

[faxmunky]

Hello,

I'm creating a game and I'm planning on adding in throwable items that incorporate gravity (Like grenades).

I've come up with some code here, it collides with the bottem of the stage which is 400 on the y axis. But I've decided that I do not want it to bounce from the bottom of the stage, I want it to bounce from the scenery ground. This ground may not be perfectly flat and may have hills or obstacles.

Here is my code.

onClipEvent(load){
	var ground:Number = 400;
        var yVel:Number = 0;
	var gravity:Number = 2;
	var radius:Number = this._height/2; //Not 100% sure
	var bounce:Number = -.85;
	var xVel:Number = 15;
	var xDec:Number = 0.3;
}

onClipEvent(enterFrame){
	this._x += xVel;
	if(xVel>0){
		xVel = xVel-xDec;
	}
}

onClipEvent(enterFrame){
		var y:Number = this._y
}

onClipEvent(enterFrame){
	yVel += gravity;
	this._y += yVel;
	if(this._y+radius>ground){
		yVel *= bounce;
		this._y = ground-radius;
	}
}
on (press) {
	yVel = 0
	gravity = 0
	startDrag(_root.grenade);
}

on (release) {
	yVel = 0
	gravity = 1
	stopDrag();
}

So, what I am trying to do is remove the entire 'ground' variable which is a y co-ordinate and replace it with a hitTest for _root.ground. I'm just feeling tired and I'm not sure exactly how I would do this.

All comments and help are greatly appreciated.

Thanks,
Faxmunky

[OctoFlash]

okay, first of all: is this your code? or did you just copy and paste it? i mean: do you understand what you are showing use here? because if you want to work with this kind of codes you gotta know how to use them..

[faxmunky]

At 1/30/09 06:59 AM, OctoFlash wrote: okay, first of all: is this your code? or did you just copy and paste it? i mean: do you understand what you are showing use here? because if you want to work with this kind of codes you gotta know how to use them..

I wrote this code myself. I did not copy and paste. I understand it.

[BillysProgrammer]

If you even had a thought to program, we would see more posts on here lol. Also, you would know not to use more then 1 clipEvent, enterFrame etc.

[Munz]

no this guys ligit i know him

[BillysProgrammer]

Not really trying to imply that he's lying. Because personally, I am not sure and I do not know him. If you know he's legit, then there's no problem here.

[Nuttro]

Well personally I think it was copied and pasted the way it's set out

[ThePeasant]

doing collision testing for circles is apparently complicated. I'm learning about hittests now actually, and from what I've gathered, making a square bounding box around your object and using that to test with is the easiest way to go.

Here's how to do collision testing, step by step:

1) determine the direction that an object is travelling

2) project an image in front of the object using whatever bounding points you have in that direction (for a box it is 2 or 3. For a circle it can be 20 or more... unless you use Vectors, but testing between circles and oddly shaped terrain using vectors is very confusing)

3) test to see if the image overlaps whatever you are testing against.

4) if so, react to it! In the case of a bouncing object, create a virtual 'flat plane' at the point where the object comes in contact with the ground and calculate a new trajectory as if it bounced off of that flat plane.

[faxmunky]

Firstly, I wrote this code myself full stop. I don't give a shit what you think.

At 1/30/09 07:44 AM, Munz wrote: no this guys ligit i know him

Thanks mate,

At 1/30/09 08:43 AM, ThePeasant wrote:

:An explanation that is too high a % for this post.

Thanks, that works great.

[faxmunky]

At 1/30/09 07:42 AM, BillysProgrammer wrote: If you even had a thought to program, we would see more posts on here lol. Also, you would know not to use more then 1 clipEvent, enterFrame etc.

Sorry for double post.

I use more than one clipEvent, enterFrame etc. because It's a mess if I don't. It organises it better and that's just a personal thing. I've also read that it does not slow it down. This is because when you run it, it automatically groups them altogether.